Y = x2-3x-4 x=y+8

solution set

a: { (-1,0), (4,0) }

b: { (8,0), (0,8) }

c: { (0,0) }

d: { (2,-6) }

e: there is no real solution

Plug in x into first equation

Y = (y+8) ^2-3 (y+8) - 4

Y=y2+16y+64-3y-24-4

Y=y2+13y+36

Y = (y+9) (y+4)

Y = - 9,-4 plug in - 9 to find x n plug in - 4 to find its x

X=y+8

X=-9+8 x=-1 Plug in - 1 into first equation

Y=x2-3x-4

Y=-1^2+3-4

Y = 1+3-4

Y=0

(-1,0) do the same for - 4

X=y+8

X=-4+8

X=4

Y=x2-3x-4

Y=4^2-12-4

Y=16-16

Y=0

(4,0)

Solutions are (-1,0) (4,0)