Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/s. when sharon jumps, megan throws a beach ball up to sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground. to the nearest hundredth of a second, how long after she jumps does the ball reach sharon? 0.65 seconds 0.92 seconds 1.08 seconds 1.15 seconds

Question

Mathematics

Malcolm Mcdaniel

30 December, 07:19

Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/s. when sharon jumps, megan throws a beach ball up to sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground. to the nearest hundredth of a second, how long after she jumps does the ball reach sharon? 0.65 seconds 0.92 seconds 1.08 seconds 1.15 seconds

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Answers (1)

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Armando Poole · Answer 1

Sharon position, S (t) = 18 + 4t - 16t^2

Ball position, B (t) = 5 + 16t - 16t^2

S (t) = B (t)

18 + 4t - 16t^2 = 5 + 16t - 16t^2

16t - 4t = 18 - 5

12t = 13

t = 13/12 = 1.08

Answer: t = 1.08 seconds

t =