Identify the axis of symmetry and vertex of f (x) = - x^ 2 - 2x-1.

Axis of symmetry: x = - 1; Vertex: (1, 0)

Axis of symmetry: x = 1; Vertex: (1, 0)

Axis of symmetry: x = - 1; Vertex: ( - 1, 0)

Axis of symmetry: x = 1; Vertex: ( - 1, - 1)

Question

Mathematics

Denisse

29 April, 05:52

Identify the axis of symmetry and vertex of f (x) = - x^ 2 - 2x-1.

Axis of symmetry: x = - 1; Vertex: (1, 0)

Axis of symmetry: x = 1; Vertex: (1, 0)

Axis of symmetry: x = - 1; Vertex: ( - 1, 0)

Axis of symmetry: x = 1; Vertex: ( - 1, - 1)

+3

Answers (1)

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Carolina Whitney · Answer 1

Axis of symmetry formula = - b/2a

x = - (-2) / 2 (-1)

x=2/-2

x=-1

sub - 1 into original equation

y = - (-1) ^2-2 (-1) - 1

y=-1+2-1

y=0

vertex = (-1, 0)

Identify the axis of symmetry and vertex of f (x) = - x^ 2 - 2x-1.Axis of symmetry: x = - 1; Vertex: (1, 0)Axis of symmetry: x = 1; Vertex: (1, 0)Axis of symmetry: x = - 1; Vertex: ( - 1, 0)Axis of symmetry: x = 1; Vertex: ( - 1, - 1)

Identify the axis of symmetry and vertex of f (x) = - x^ 2 - 2x-1.

Axis of symmetry: x = - 1; Vertex: (1, 0)

Axis of symmetry: x = 1; Vertex: (1, 0)

Axis of symmetry: x = - 1; Vertex: ( - 1, 0)

Axis of symmetry: x = 1; Vertex: ( - 1, - 1)