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9 February, 15:35

What is the question? compare: 17,643251; 17633512; and 17633893

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  1. 9 February, 16:29
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    Hello,

    All numbers are integers.

    The number having the most number of digits is the greater.

    But we are not lucky they have all 8 digits.

    We must begin to compare the left most digit

    Let's call p the position from left of the digit we examine.

    We call x1, x2, x3 the numbers.

    p=1: n1 (p) = 1; n2 (p) = 1; n3 (p) = 1 : we must go further

    p=2: n1 (p) = 7; n2 (p) = 7; n3 (p) = 7 : we must go further

    p=3: n1 (p) = 6; n2 (p) = 6; n3 (p) = 6 : we must go further

    p=4: n1 (p) = 4; n2 (p) = 3; n3 (p) = 3 : so n1 is the greater but we must go further

    p=5: n2 (p) = 3; n3 (p) = 3 : we must go further

    p=6: n2 (p) = 5; n3 (p) = 8 : n2 is the median, and n3 the smallest

    so n2
    or 17633512<17633893< 17,643251

    I have explain as i were a cumputer.
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