The vertex form of the equation of a parabola is x = 8 (y - 1) 2 - 15. What is the standard form of the equation?

A:x = 8y^2 - 16y - 7

B. x = 16y^2 - 2y - 16

C. x = 8y^2 - 4y + 32

D. x = 16y^2 - 4y + 32

Question

Branden Love

13 December, 16:50

+5

Answers (1)

Know the Answer?

Virginia Fitzgerald · Answer 1

Just expand

x=8 (y-1) ^2-15

x=8 (y-1) (y-1) - 15

x=8 (y²-2y+1) - 15

x=8y²-16y+8-15

x=8y²-16y-7

A is answer

The vertex form of the equation of a parabola is x = 8 (y - 1) 2 - 15. What is the standard form of the equation?A:x = 8y^2 - 16y - 7B. x = 16y^2 - 2y - 16C. x = 8y^2 - 4y + 32D. x = 16y^2 - 4y + 32