If f (x) = - 2x^3, g (x) = 3x-5, and h (x) = x-1, what is f (g (h (3))) ?

A) - 129

B) - 54

C) - 53

D) - 2

F (g (h (3)))

find h (3)

h (3) = 3-1=2

now

f (g (h (3)) = f (g (2))

find g (2)

g (2) = 3 (2) - 5=6-5=1

now

f (g (h (3))) = f (g (2)) = f (1)

find f (1)

f (1) = - 2 (1) ^3

f (1) = - 2 (1)

f (1) = - 2

answer is D