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13 March, 00:28

Solve by elimination

-4x-5y-z=18

-2x-5y-2z=12

-2x+5y+2z=4

+3
Answers (2)
  1. 13 March, 04:03
    0
    So

    -4x-5y-z=18

    -2x-5y-2z=12

    -2x+5y+2z=4

    the 2 last equations look perfect for canceling each other so add them together

    -2x-5y-2z=12

    -2x+5y+2z=4 +

    -4x+0y+0z=16

    -4x=16

    divide both sides by 4

    -x=4

    multiply - 1

    x=-4

    now we have

    -4x-5y-z=18

    -2x+5y+2z=4

    add them together

    -6x+0y+z=22

    but x=-4 so

    -6 (-4) + z=22

    24+z=22

    subtract 24 from both sides

    z = - 2

    subsitute into any equation

    -2x-5y-2z=12

    x=-4

    z=-2

    -2 (-4) - 5y-2 (-2) = 12

    8-5y+4=12

    12-5y=12

    subtract 12 from both sides

    -5y=0

    y=0

    x=-4

    y=0

    z=-2
  2. 13 March, 04:15
    0
    -4x - 5y - 1z = 18 ⇒ - 4x - 5y - 1z = 18

    -2x - 5y - 2z = 12 ⇒ - 2x - 5y - 2z = 12

    -2x + 5y + 2z = 4 - 6x - 10y - 3z = 30

    -6 (-4) - 10y - 3z = 30

    -4x - 5y - 1z = 18 24 - 10y - 3z = 30

    -2x - 5y - 2z = 12 ⇒ - 2x - 5y - 2z = 12 - 24 - 24

    -2x + 5y + 2z = 4 ⇒ - 2x + 5y + 2z = 4 - 10y - 3z = 6

    -4x = 16 - 10y + 10y - 3z = 6 + 10y

    -4 - 4 - 3z = 6 + 10y

    x = - 4 - 3 - 3

    z = - 2 - 3¹/₃y

    -10y - 3 (-2 - 3¹/₃y) = 6

    -10y + 6 + 10y = 6

    -10y + 10y + 6 = 6

    0y + 6 = 6

    - 6 - 6

    0y = 0

    0 0

    y = 0

    -10 (0) - 3z = 6

    -0 - 3z = 6

    0 - 3z = 6

    - 0 - 0

    -3z = 6

    -3 - 3

    z = - 2

    (x, y, z) = (-4, 0, - 2)
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