Y=*^2+4x+1 and y=x+1

Solve a linear/quadratic system by graphing and substitution.

Graphing is used when you have paper

I will not graph this equation because it takes time, sorry

but I will solve

subsitute y=x^2+4x+1

subsitute x+1 for y

x+1=x^2+4x+1

subtract x from bot sides

1=x^2+3x+1

subtract 1 from both sides

0=x^2+3x

factor

0 = (x) (x+3)

if xy=0 then assume that x and y=0

so

set them to zero

x=0

x+3=0

subtract 3 from both sides

x=-3

subsitue

y=x+1

y=0+1

y=1

y=-3+1

y=-2

so the answers could be

(x, y)

(-3,-2)

(0,1)