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6 February, 12:44

Y=*^2+4x+1 and y=x+1

Solve a linear/quadratic system by graphing and substitution.

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Answers (1)
  1. 6 February, 15:49
    0
    Graphing is used when you have paper

    I will not graph this equation because it takes time, sorry

    but I will solve

    subsitute y=x^2+4x+1

    subsitute x+1 for y

    x+1=x^2+4x+1

    subtract x from bot sides

    1=x^2+3x+1

    subtract 1 from both sides

    0=x^2+3x

    factor

    0 = (x) (x+3)

    if xy=0 then assume that x and y=0

    so

    set them to zero

    x=0

    x+3=0

    subtract 3 from both sides

    x=-3

    subsitue

    y=x+1

    y=0+1

    y=1

    y=-3+1

    y=-2

    so the answers could be

    (x, y)

    (-3,-2)

    (0,1)
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