What is the standard form of the equation for this circle 4, - 5 radius 5.5

Standard form of equation of a circle:

(x - a) ^2 + (y - b) ^2 = r ^2.

Where centre = (a, b)

r = radius.

Centre (4, - 5) = (a, b), a = 4, b = - 5.

r = 5.5.

(x - 4) ^2 + (y - - 5) ^2 = 5.5^2

(x - 4) ^2 + (y + 5) ^2 = 5.5^2 Expand brackets, and use your calculator

x^2 - 8x + 16 + y^2 + 10y + 25 = 30.25

x^2 - 8x + y^2 + 10y + 25 + 16 - 30.25 = 0

x^2 - 8x + y^2 + 10y - 10.25 = 0.

x^2 + y^2 - 8x + 10y - 10.25 = 0. That's the equation of the circle.

or 10.25 = 10 / 1/4 = 41/4

x^2 + y^2 - 8x + 10y - 41/4 = 0 Multiply both sides of the equation by 4.

4x^2 + 4y^2 - 32x + 40y - 41 = 0

Cheers.