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29 April, 18:15

What is the standard form of the equation for this circle 4, - 5 radius 5.5

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  1. 29 April, 19:56
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    Standard form of equation of a circle:

    (x - a) ^2 + (y - b) ^2 = r ^2.

    Where centre = (a, b)

    r = radius.

    Centre (4, - 5) = (a, b), a = 4, b = - 5.

    r = 5.5.

    (x - 4) ^2 + (y - - 5) ^2 = 5.5^2

    (x - 4) ^2 + (y + 5) ^2 = 5.5^2 Expand brackets, and use your calculator

    x^2 - 8x + 16 + y^2 + 10y + 25 = 30.25

    x^2 - 8x + y^2 + 10y + 25 + 16 - 30.25 = 0

    x^2 - 8x + y^2 + 10y - 10.25 = 0.

    x^2 + y^2 - 8x + 10y - 10.25 = 0. That's the equation of the circle.

    or 10.25 = 10 / 1/4 = 41/4

    x^2 + y^2 - 8x + 10y - 41/4 = 0 Multiply both sides of the equation by 4.

    4x^2 + 4y^2 - 32x + 40y - 41 = 0

    Cheers.
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