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17 May, 10:11

Wyatt's eye-level height is 120 ft above sea level, and Shawn's eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = square root of 3h/2, h>0 with d being the distance they can see in miles and h being their eye-level height in feet.

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  1. 17 May, 13:40
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    Using the formula given: d = √ (3h/2)

    We simply substitute the given values of h into the equation and compare the results.

    For Wyatt where h = 120:

    d = √ (3 (120) / 2)

    d = 13.42 miles

    For Shawn where h = 270:

    d = √ (3 (270) / 2)

    d = 20.12 miles

    Since the question asks for how much farther can Shawn see, we subtract the results:

    20.12 - 13.42 = 6.7

    Therefore, Shawn can see 6.7 miles farther.
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