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16 October, 11:49

Three terms, 19-6x, 2 + 4x, 6x + 1, are in arithmetic progression.

a) Calculate the value of x.

+1
Answers (1)
  1. 16 October, 14:29
    0
    So therfor from 19-6x to 2+4x the diffence if the same as the diffence between 2+4x an d6x+1

    so (2+4x) - (19-6x) = (6x+1) - (2+4x)

    add like terms

    2+4x-19+6x=6x+1-2-4x

    10x-17=2x-1

    add 17 to both sdies

    10x-2x+16

    subtract 2x form both sdies

    8x=16

    divide boht sdie syb 8

    x=2

    x=2

    therfor the terms are

    7, 10, 13
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