If f (x) = (x^1/2 - x)

And g (x) = (2x^3 - x^1/2 - x)

Find f (x) - g (x)

A.) - 2x^3 - 2x - 2x^1/2

B.) - 2x^3 - 2x

C.) 2x^3 - 2x + 2x^1/2

D.) - 2x^3 + 2x^1/2

Also give a brief explanation, I know how to set up the problem, just not sure what to do after you have

X^1/2 - x - 2x^2 - x^1/2 - x

Question

Mathematics

Mary

28 February, 17:53

If f (x) = (x^1/2 - x)

And g (x) = (2x^3 - x^1/2 - x)

Find f (x) - g (x)

A.) - 2x^3 - 2x - 2x^1/2

B.) - 2x^3 - 2x

C.) 2x^3 - 2x + 2x^1/2

D.) - 2x^3 + 2x^1/2

Also give a brief explanation, I know how to set up the problem, just not sure what to do after you have

X^1/2 - x - 2x^2 - x^1/2 - x

+3

Answers (1)

Know the Answer?

Essence Jimenez · Answer 1

Well, you are subtracting g (x) from f (x) so:

√x-x - (2x^3-√x-x) which is:

√x-x-2x^3+√x+x (you have your signs wrong at the bottom of your post)

Now you would simply combine like terms (do your addition and subtraction of like terms)

-2x^3+2√x

So the answer is D.

If f (x) = (x^1/2 - x)And g (x) = (2x^3 - x^1/2 - x)Find f (x) - g (x)A.) - 2x^3 - 2x - 2x^1/2B.) - 2x^3 - 2xC.) 2x^3 - 2x + 2x^1/2D.) - 2x^3 + 2x^1/2Also give a brief explanation, I know how to set up the problem, just not sure what to do after you haveX^1/2 - x - 2x^2 - x^1/2 - x

If f (x) = (x^1/2 - x)

And g (x) = (2x^3 - x^1/2 - x)

Find f (x) - g (x)

A.) - 2x^3 - 2x - 2x^1/2

B.) - 2x^3 - 2x

C.) 2x^3 - 2x + 2x^1/2

D.) - 2x^3 + 2x^1/2

Also give a brief explanation, I know how to set up the problem, just not sure what to do after you have

X^1/2 - x - 2x^2 - x^1/2 - x