The sides of a triangle have lengths of x, x+2, and 2x-40, the perimter is 70 cm find the length of each side of the triangle

If the length of three sides are x, x+2, and 2x-40. Then x=27.

Because the perimeter of the triangle is the sum of the length of sides of the triangle. (3 sides. Since it's a triangle). Therefore,

the perimeter of the traingle = Length of side 1 + Length of side 2 + Length of side 3.

The lengths given are 1) x, 2) x+2, 3) 2x-40.

Therefore.

Perimeter = x + x+2 + 2x-40.

And since perimeter is equal to 70cm.

70 = x + x+2 + 2x-40.

70 = x + x + 2x - 40 + 2.

70 = 4x - 38

70+38 = 4x

108=4x

108/4=x

x=27.

Therefore.

length 1, which was x, is equal to 27.

length 2, which was x+2, is equal to (27+2) = 29.

length 3, which was 2x-40, is equal to ((2*27) - 40) = 14.

X + (x+2) + (2x - 40) = 70 cm

4x + 2 - 40 = 70

4x - 38 = 70

4x = 70 + 38 = 108

x = (108/4) = 27 cm

So: 1stlength = x = 27cm

2nd length = x+2 = 27+2 = 29 cm

2rd length = 2x - 40 = 2*27 - 40 = 54 - 40 = 14 cm

Sthe Perimeter = 27+29+14 = 70 cm