Is two thirds of the girl in the class have brown eyes and one fourth of the girls have blue eyes what fraction of the girls in class have neither blue or brown eyes

Well you have to make the fractions have equal denominators so multiply one fractions numerator and denominator by the other fractions denominator then do the same with the other fraction

2/3 times 4 = 8/12

1/4 times 3 = 3/12

add the fractions together to get 12/12

so 0/12 have neither brown or blue eyes