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8 January, 14:56

What is the value of b^2-4ac for the following equation 10x^2-19x+6=0

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  1. 8 January, 18:25
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    B^2 - 4ac

    10x^2 - 19x + 6 = 0

    This is for the quadratic formula

    Your a value is the scalar of the x^2 (10)

    Your b value is the scalar of the x (-19)

    Your c value is the constant (6)
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