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Mathematics
Mike Mccullough
27 April, 19:18
5 consecutive integers of 265
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Tyrell Guzman
27 April, 20:32
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N+n+1+n+2+n+3+n+4=265
5n+10=265
5n=255
n=51
So the integers are:
51,52,53,54, and 55
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