What is the area of a triangle whose vertices are R (-4,2), S (1,2), and T (-5,-4) ?

Fisrt is solve the distance of the segments using distance formula

Distance = sqroot[ (x2-x1) ^2 + (y2-y1) ^2]

So ditance of RS = 5

ST = 8.49

TR = 6.08

The using herons formula

Area = sqrt (s (s-a) (s-b) (s-c))

Where s s = 1/2 (a + b + c)

And a, b, c are length of the sides

S = 9.785

Area = 14.99