Rewrite the equation in vertex form. x^2+10x+16

We can determine the vertex form of this equation by using the technique completing the squares

y = x^ 2 - 10x + 16

(k/2) ^2 = (-10/2) ^2 = 25

x^2 - 10x + 16 + 25 = y + 25

x^2 - 10x + 25 = y + 25 - 16

(x - 5) ^2 = y + 9

h is equal to 5 and k is equal to - 9. 4a is equal to 1