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Ana Carter
5 March, 16:08
How would you solve 3sin0=sin0-1
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Issac Henry
5 March, 16:45
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3sinΘ = sinΘ - 1
3sinΘ - sinΘ = sinΘ - sinΘ - 1
2sinΘ = - 1
2sin 2sin
Θ = - 2.864934497
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Corbin Hendrix
5 March, 19:49
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I would subtract 1sin (Θ) from each side of the equation.
The equation would then say that 2sin (Θ) = - 1.
I would only have to find angles whose sin is - 1/2,
and those would be my solutions.
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