What are the coordinates of the x and y intercepts of the equation 3x+2y=12

To find the x-intercept you must make y=0

3x+2y=12 - substitute 0 for y

3x+2 (0) = 12 - multiply 2 and 0

3x+0=12 - add zero

3x=12 - divide by 3

x=4

To find the y-intercept you must make x=0

3x+2y=12 - substitute 0 for x

3 (0) + 2y=12 - multiply 3 and 0

0+2y=12 - add 0 and 2y

2y=12 - divide by 2

y=6