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15 May, 10:58

The perimeter of a rectangle is 36 and the length is twice the width. What are the dimensions of this rectangle and what is the area?

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  1. 15 May, 14:29
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    let l be the length and w be the width.

    so 2l + 2w = 36

    also, l = 2w,

    Putting the value for l in the first equation:

    2 (2w) + 2w = 36

    4w + 2w = 26

    6w = 36

    w = 6

    now solving for the length:

    l = 2w

    l = 2 (6)

    so the length will be 12, l = 12

    So the width is 6. the length is 12.

    and the area is lxw, so the area will be 72
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