What is the absolute value of - 4-√2i

For x + iy absolute value = √ (x² + y²)

Absolute value of - 4-√2i = - 4-i√2, comparing x = - 4, y = - √2

Absolute value = √ ((-4) ² + (-√2) ²),

(-4) ² = (-4) * (-4) = 16, (-√2) ² = - √2 * - √2 = 2

= √ ((-4) ² + (-√2) ²)

= √ (16 + 4) = √20

√20 = √ (4*5) = √4 * √5 = 2√5

Absolute value = 2√5