A jar contains 3 blue marbles, 6 red marbles, 1 green marble, and 2 black marbles. A marble is chosen at random from the jar and replaced. Then another marble is chosen at random. Find the probability of the first marble being red and the second marble being green.

1⁄2 = 50%

7⁄24 = 29.2%

7⁄12 = 58.3%

1⁄24 = 4.2%

7⁄144 = 4.9%

Question

Randall Sutton

12 July, 04:40

+5

Answers (1)

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Ireland Sullivan · Answer 1

7/12=29.2%

you add up the total number of marbles twice since you drew out of them twice and add the total number of red and green marbles together.