Find the surface area of the pyramid with square base that measures 8 ft by 8 ft and slant height of 12 ft.

Slant surface is composed of 4 triangles each of 8' base B and height H of 12'.

Area of each triangle is therefore

A = (1/2) BH

= (1/2) (8) (12)

=48 sq. ft

Total slant surface area = 4A = 192 sq. ft.

Area of square base = 8*8 = 64 sq. ft

Total surface area = 192+64 = 256 sq. ft.

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