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21 January, 13:57

The perimeters of a rectangle and an equilateral triangle are equal. The length of the rectangle is twice the width, and the side of the triangle is 8 more than the width of the rectangle. Which statements about this scenario are true if we use the variable w to represent the width of the rectangle?

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  1. 21 January, 15:44
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    The perimeter of triangle is 3 (w+8) = 3w + 24

    The perimeter of rectangle is w+w+2w+2w = 6w

    Set them equal to solve for w:

    6w = 3w + 24

    3w = 24

    w = 8
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