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7 April, 22:29

Solve the system below

y=x^2-2x-6

y=4x+10

A. (-2,2)

B. (8,42)

C. (-2,2), (8,42)

D. No real solution

Solve the system below

y=x^2 - 4

y = - 4

A. (0,-4)

B. (-4,0)

C. (0,-4), (-4,0)

D. No real solution

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Answers (1)
  1. 7 April, 23:30
    0
    For the system y=x^2-2x-6 & y=4x+10 the answer is A. (-2,2)

    y=-2^2-2 (-2) - 6

    y=4+4-6

    y=8-6

    y=2

    y=4x+10

    y=4 (-2) + 10

    y=-8+10

    y=2

    For the system y=x^2-4 & y=-4 the answer is

    A. (0,-4)

    y=0^2-4

    y=-&

    For the system
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