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18 September, 04:25

What is the value of y in the product of powers below?

8^3*8^-5*8^y=8^-2=1/8^2

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Answers (2)
  1. 18 September, 06:48
    0
    You're trying to find the value of y that would result in 8^-2. When you multiply terms with the same base, you can add the exponents. 3+-5=-2 and - 2 - (-2) equals 0, so therefore y is equal to 0.
  2. 18 September, 07:47
    0
    8^-2=1/8^2 so just use 8^-2

    8^3*8^-5*8^y=8^-2

    8^ (3-5+y) = 8^-2

    3-5+y=-2

    y=0
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