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23 December, 06:34

The sum of 5 consecutive integers is 205. What is the third number?

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  1. 23 December, 07:47
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    If 5 consecutive integers is 205,

    then a + b + c + d + e = 205

    but also, each integer is separated by a difference of 1

    ⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205

    ⇒ 5a + 10 = 205

    ⇒ 5a = 195

    ⇒ a = 39

    ∴ third term = 39 + 2

    = 41
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