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11 September, 08:43

How many 6 digit odd numbers are possible if the leftmost digit cannot be zero?

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Answers (2)
  1. 11 September, 09:59
    0
    There are 9 choices for the first digit: 1,2,3,4,5,6,7,8,9

    There are 10 choices for the second digit: 0,1,2,3,4,5,6,7,8,9

    There are 5 choices for the third digit: 1,3,5,7,9

    That's 9*10*5 = 450
  2. 11 September, 12:26
    0
    The correct answer is 9 x 5 x 10 = 450
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