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15 January, 03:17

Sandy is upgrading her internet service. Fast internet charges $60 for installation and $50.45 per month. Quick internet has free installation but charges $57.95 per months. write an equation that can be used to find the number of months at which the internet service would cost the same and solve the equation.

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  1. 15 January, 04:35
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    Let's let x equal the number of months that payment is made.

    $60 is constant, because it is only charged once.

    Let's let y equal the total cost for x amount of months.

    For fast internet:

    y=50.45x+60

    For quick internet:

    y=57.95x

    The equations will equal each other when the payment has reached the same amount.

    50.45x+60=57.95x
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