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11 May, 00:06

The product of 7 and a nimber increased by 3 is equal to twice the number subtracted from 39

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  1. 11 May, 02:25
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    Let the number is = x

    So number increased by 3 is = x+3.

    So product of 7 and (x+3) is = 7 * (x+3).

    Twice of number is = 2x

    So we can write

    7 (x+3) = 39 - 2x

    7x + 21 = 39 - 2x

    Now we can arrange the term as

    7x + 2x = 39 - 21

    9x = 18

    x = 2.

    SO the number is 2.
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