If f (x) = sqrt of (4sinx+2) then f' (0) =

We are given the function f (x) = sqrt of (4sinx+2) and is asked to find the first derivative of the function when x is equal to zero.

f (x) = sqrt of (4sinx+2)

f' (x) = 0.5 (4sinx+2) ^ - 0.5 * (4cosx)

f' (0) = 0.5 (4sin0+2) ^ - 0.5 * (4cos0)

f' (0) = 0.5 (0+2) ^ - 0.5 * (4*1)

f' (x) = 0.5 (2) ^ - 0.5 * (4)

f' (x) = -.1.65