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27 March, 17:10

What are the coordinates of the center of the circle if this is its equation:

x2 + y2 - 16x + 6y + 53 = 0

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  1. 27 March, 20:49
    0
    Hello,

    x²-16x+y²+6y+53=0

    ==>x²-2*8*x+8² + y²+2*3*y+3²+53-64-9=0

    ==> (x-8) ² + (y+3) ²=20

    Center is (8,-3) and radius = √20
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