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31 August, 20:13

Derek kicks a soccer ball off the ground and in the air with an initial velocity of 31 feet per second. Using the formula H (t) = - 16t2 + vt + s, what is the maximum height the soccer ball reaches?

14.2 feet

14.6 feet

15.0 feet

15.3 feet

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Answers (2)
  1. 31 August, 21:10
    0
    The answer to this question is:

    C: 15.0 feet
  2. 31 August, 22:36
    0
    Given v=31 and s=0

    H (t) = - 16t2 + vt + s

    H (t) = - 16t^2 + 31t

    dH/dt = - 32t + 31

    At the maximum height, dH/dt = 0

    -32t + 31 = 0

    t = 31/32 =.96875

    substitute back to H (t)

    H (.96875) = 15.0 ft

    ans is C
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