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16 October, 00:55

Sighting the top of a building, a surveyor measured the angle of elevation to be 60 degrees. The measurement is taken 200 feet from the building. Find the building's height. Express your answer in terms of feet and then round to two decimls.

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  1. 16 October, 02:54
    0
    Tan (60) = opposite/200

    height = 200tan (60) = 200sqrt (3) or about

    346.41 ft
  2. 16 October, 03:38
    0
    This is a 30-60-90 triangle

    opposite side of rigt angle=2x

    opposite side of 60 degrees is x√3

    opposite sides of 30 degree is x

    the right angle is at the base of the building so therefor

    200=x

    2x=distance from surveor to top of building and x√3=height of building

    x=200

    200√3≈346.41

    the answer is 346.41 feet
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