3r (2p-5) - p (2p-5) factorise it

Question

Mathematics

Asa Pennington

14 May, 10:56

3r (2p-5) - p (2p-5) factorise it

+3

Answers (2)

Know the Answer?

Lucia Jarvis · Answer 1

3r (2p - 5) - p (2p - 5)

let a = 2p - 5

3r (2p - 5) - p (2p - 5) = 3ra - pa = a (3r - p)

let's substitute back the value of a.

a (3r - p) = (2p - 5) (3r - p)

Therefore: 3r (2p - 5) - p (2p - 5) = (2p - 5) (3r - p)

Tyrese Todd · Answer 2

3r (2p - 5) - p (2p - 5)

The common factor is (2p - 5), therefore we can write:

(2p - 5) (3r - p)