A manufacturer of lighting fixtures has daily production costs of

C = 800 - 40x + 0.25x2,

where C is the total cost (in dollars) and x is the number of units produced. How many fixtures should be produced each day to yield a minimum cost?

Question

Mathematics

Monster

23 January, 03:20

A manufacturer of lighting fixtures has daily production costs of

C = 800 - 40x + 0.25x2,

where C is the total cost (in dollars) and x is the number of units produced. How many fixtures should be produced each day to yield a minimum cost?

+5

Answers (1)

Know the Answer?

Teagan Kirk · Answer 1

To calculate this we need to find derivative of C

C' = - 40 + 0.5x = 0

x = 40/0.5 = 80

Every time you have a function that depends on some variable and you need to calculate minimum or maximum, make derivative of it and set it equal to 0

A manufacturer of lighting fixtures has daily production costs ofC = 800 - 40x + 0.25x2,where C is the total cost (in dollars) and x is the number of units produced. How many fixtures should be produced each day to yield a minimum cost?

A manufacturer of lighting fixtures has daily production costs of

C = 800 - 40x + 0.25x2,

where C is the total cost (in dollars) and x is the number of units produced. How many fixtures should be produced each day to yield a minimum cost?