Two trains, train A and train B simultaneously depart station A and station B. Station A and station B are 252.5 miles apart from each other. Train A is moving 124.7mph towards Station B, and train B is moving 253.5mph torwards station A. If both trains depart at 10:00 and it is now 10:08, how much longer until both trains pass each other?

Question

Mathematics

Rolando Villanueva

Yesterday, 23:55

Two trains, train A and train B simultaneously depart station A and station B. Station A and station B are 252.5 miles apart from each other. Train A is moving 124.7mph towards Station B, and train B is moving 253.5mph torwards station A. If both trains depart at 10:00 and it is now 10:08, how much longer until both trains pass each other?

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Charlize Pennington · Answer 1

time is equal to velocity divide distance ... t=v/d

time = v (252.5) / d (378.2) =.67 hours - - > 40 min ... 40 - 8 = 32 min

add 252.5 + 124.7 = 378.2

1 hour = 60 min thus, 60 min *.67 hours = 40 min

rebember that 8 min already passed thats why 40 - 8 = 32 min