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12 June, 15:01

Solve using substitution. (C& D)

2C+3D=1

-3C+D=15

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Answers (2)
  1. 12 June, 17:56
    0
    Equation 2

    -3c+d=15

    d=15+3c

    Substitute into eq 1

    2c+3 (15+3c) = 1

    2c+45+9c=1

    11c=-44

    c=-44/11

    c=-4

    Sub into eq 1

    2 (-4) + 3d=1

    -8+3d=1

    3d=9

    d=9/3

    d=3

    Verify:

    2 (-4) + 3 (3) = 1

    -8+9=1

    1=1 - - True.
  2. 12 June, 18:18
    0
    2c + 3d = 1 ⇒ 2c + 3d = 1 ⇒ 2c + 3d = 1

    -3c + d = 15 ⇒ 3 (-3c + d) = 15 ⇒ - 9c + 3d = 15

    -7c = 16

    -7c = 16

    -7 - 7

    c = - 2 2/7

    2 (2 2/7) + 3d = 1

    4 4/7 + 3d = 1

    -4 4/7 - 4 4/7

    3d = - 3 4/7

    3d = - 3 4/7

    3 3

    d = - 1 4/21

    (c, d) = (-2 2/7, - 1 4/21)
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