Ask Question
24 October, 12:49

What is the minimum value of the expression $x^2+y^2-6x+4y+18$ for real $x$ and $y$?

+3
Answers (1)
  1. 24 October, 14:26
    0
    X^2+y^2-6x+4y+18=0

    x^2-6x+y^2+4y+18=0

    x^2-6x+9+y^2+4y+4 = - 18+9+4

    (x-3) ^2 + (y+2) ^2=-5

    -5 is the minimum value of the given circle
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the minimum value of the expression $x^2+y^2-6x+4y+18$ for real $x$ and $y$? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers