Three consecutive odd intergers have a sum of 27. find the integers

Solve for x:

x + (x + 2) + (x + 4) = 27

3x + 6 = 27

3x = 27 - 6

3x = 21

3x / 3 = 21 / 3

x = 7

The integers:

x + (x + 2) + (x + 4) = 27

7 + (7 + 2) + (7 + 4) = 27

7 + 9 + 11 = 27

27 = 27

The integers are 7, 9, 11