If x is normally distributed random variable with a mean of 8.20 and variance of 4.41, and that p (x >

b. =.08, then the value of b is:

Question

Mathematics

Weston

12 February, 06:12

If x is normally distributed random variable with a mean of 8.20 and variance of 4.41, and that p (x >

b. =.08, then the value of b is:

+1

Answers (1)

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Aurora Sherman · Answer 1

Given that mean is 8.20 and variance is 4.41, the value of b will be calculated as follows:

P (x>b) = 0.08

⇒P (x
the z-score corresponding to this probability is:

z=1.41

but the formula for z-score is given by:

z = (x-μ) / σ

where:

μ=mean

σ=standard deviation

thus plugging in the values we obtain:

1.41 = (x-8.2) / √4.41

1.41 = (x-8.2) / 2.1

solving for x

1.41*2.1=x-8.2

x=2.961+8.2

x=11.161

Hence the answer is x=11.161

If x is normally distributed random variable with a mean of 8.20 and variance of 4.41, and that p (x >b. =.08, then the value of b is:

If x is normally distributed random variable with a mean of 8.20 and variance of 4.41, and that p (x >

b. =.08, then the value of b is: