Find 3 consecutive integers such that the sum of smallest and five times the largest is 196

Let x is the smallest integer

x+1 is the middle integer

x+2 is the largest integer

sum of smallest and five times the largest is 196

x + 5 (x + 2) = 196

x + 5x + 10 = 196

6x + 10 = 196

6x = 186

x = 186/6

x = 31

x+1 = 31+1 = 32

x+2 = 31+2 = 33

proof:

sum of smallest and five times the largest is 196

x + 5 (x + 2) = 196

31+5 (31+2) = 196

31+5 (33) = 196

31+165=196

196=196 ... > true

answer:

3 consecutive integers are 31,32,33