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9 May, 02:38

A rectangle has a length that is nine feet less than four times its width. its area is 90 square feet. Algebraically determine the length of its width and length. show the work that leads to your answer.

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  1. 9 May, 02:48
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    Let width = 4x

    Therefore length must equal 4x - 9

    4x + 4x - 9 = 90

    8x - 9 = 90

    (plus 9 to both sides)

    8x = 99

    (divide both sides by 8)

    x = 12.375

    width = 4 x 12.375

    width = 49.5

    length = 49.5 - 9

    length = 40.5
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