Ask Question
19 November, 08:56

Solve x^2 - 6x + 63 = 0 in a + bi form

+2
Answers (1)
  1. 19 November, 10:06
    0
    The square root of a negative number does not exist in the set of real numbers
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve x^2 - 6x + 63 = 0 in a + bi form ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers