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24 January, 01:09

If d varies directly with t^2, and d=192 when t=8, find d when t=6

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  1. 24 January, 04:09
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    As d=k t^2 so putting d = 192 for t = 8 we get k = 192 / (8^2) = 3 so k=3

    thus d = 3t^2

    now if t=6 the d = 3 * (6^2) = 3*36

    so d = 108
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