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29 May, 23:41

What interval includes all possible values of x, where - 3 (6 - 2x) ≥ 4x + 12?

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  1. 30 May, 01:42
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    Well, we need to solve the inequality in terms of x ...

    -3 (6-2x) ≥4x+12 carry out indicated multiplication on left side

    -18+6x≥4x+12 subtract 4x from both sides

    -18+2x≥12 add 18 to both sides

    2x≥30 divide both sides by 2

    x≥15, in interval notation:

    x=[15, + oo)
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