4x+3y=14 and 6x-5y=40

Let's solve this system using elimination by addition/subtraction.

Note that if we mult. the first equation by 5, we get 20x + 15y = 70, and if we mult. the 2nd eqn by 3, we get 18x - 15y = 120.

Adding these two results together eliminates the y terms: 38x = 190. Then

x=5.

Subbing 5 for x in the 1st equation: 4 (5) + 3y = 14

20 + 3y = 14

3y = - 6

y = - 2

Then the solution is (5,-2). Check this by subbing 5 for x and - 2 for y in the 2nd equation. Is the second equation then true?