For a convex 41-gon, what is the sum of the measures of the interior angles?

Given:

convex 41-gon

n = 41

Required:

Sum of interior angles.

Solution:

To solve for the sum of interior angles, we can use the formula:

Sum of interior angles = 180 (n-2) °

Substituting,

Sum of interior angles = 180 (41-2) °

Sum of interior angles = 7020°

Therefore, the sum of the measures of the interior angle of a convex 41-gon is 7020°.