Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln (2).

Question

Mathematics

Yaka

3 May, 13:15

Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln (2).

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Answers (1)

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Ashlee Rush · Answer 1

Here's the calculation of area

π [ ln 2 + 1 / 2 sinh (2 ln 2) ]=π [ln 2 + 1 4 (2^2 - 2 ^-2) ]

=π [ln 2 + 1 / 4 (4 - 1 / 4) ]=π (ln 2 + 15 / 16) ≈ 5.122